问题描述
这是我目前所拥有的,
Socket clientSocket = new Socket(HOST, PORT); ByteArrayOutputStream buffer = new ByteArrayOutputStream(); InputStream is = socket.getInputStream(); byte[] byteChunk = new byte[1024]; int c = is.read(byteChunk); while (c != -1){ buffer.write(byteChunk, 0, c); c = is.read(byteChunk); } BufferedImage bufferedImage = ImageIO.read(new ByteArrayInputStream(buffer.toByteArray()));
我的代码的问题是 ImageIO.read() 返回 null.
My problem with my code is ImageIO.read() returns null.
当我打印 ByteArrayOutputStream 对象的内容时,我得到的是标题部分
When I print the content of ByteArrayOutputStream object what i get is header part
HTTP/1.1 200 OK Date: Fri, 30 Dec 2011 11:34:19 GMT Server: Apache/2.2.3 (Debian) ........... Last-Modified: Tue, 20 Dec 2011 19:12:23 GMT ETag: "502812-490e-4b48ad8d273c0" Accept-Ranges: bytes Content-Length: 18702 Connection: close Content-Type: image/jpeg
后跟一个空行加上许多不同字符的行,例如 à?$sU,e6?í~á?P;??....
followed with a empty line plus many lines with different characters such as à?$sU,e6?í~á?P;??….
我的问题又是 ImageIO.read() 函数返回 null.
Again my problem is ImageIO.read() function returns null.
提前致谢.
推荐答案
为什么你不想使用简单的 http URL 从主机获取图像?我的意思是:
Why you don't want to use simple http URL to get image from host? I mean:
URL imageURL = new URL("http://host:port/address"); BufferedImage bufferedImage = ImageIO.read(imageURL);
如果您想使用普通套接字,您必须手动解析 http 响应并从 http 回复中提取数据:读取/跳过标头,读取二进制数据并将其传递给 ImageIO.read(或寻求流以纠正位置并将流传递给 ImageIO.read).
If you want to use plain socket you have to parse http response and extract data from the http reply manually: read/skip headers, read binary data and pass it to ImageIO.read (or seek stream to correct position and pass stream to ImageIO.read).