问题描述
有没有办法将实体属性动态注入到@Query?我的需要是实现如下方法:
Is there a way to inject an Entity property dynamically to @Query? My need is to implement a method like follows:
@Query("select e from #{#entityName} e where e.***columnName*** = ?2") List<T> findAll(String ***columnName***, String value);
还有其他简单的方法吗?
Any other simple ways of doing this?
推荐答案
你可以使用 Spring Specification 来实现.
You can do it using Spring Specification.
您的规范方法将类似于以下一种:
Your specification method will be similar to the following one:
public static Specification<Entity> byColumnNameAndValue(String columnName, String value) { return new Specification<Entity>() { @Override public Predicate toPredicate(Root<Entity> root, CriteriaQuery<?> query, CriteriaBuilder builder) { return builder.equal(root.<String>get(columnName), value); } }; }
请阅读一下规范,这是一个很棒的工具.
Please read a little about Specification, it's a great tool.
https://spring.io/blog/2011/04/26/advanced-spring-data-jpa-specifications-and-querydsl/
和
http://docs.spring.io/spring-data/jpa/docs/current/api/org/springframework/data/jpa/domain/Specifications.html