鵞奀昆勥
问题描述
我在以下行中有语法错误.但是我不明白这个错误的原因是什么.
I have a syntax error in the following line. However I can't understand what is the reason of this error.
if (address1.compareTo(address2) = 1)
System.out.println(address1 + " is greater than " + address2);
我想要实现的是当且仅当 compareTo 返回 1 时打印正确的消息.
What I want to achieve is printing proper message if and only if compareTo returns 1.
推荐答案
你应该比较 (==) 而不是赋值 (=).这可能非常危险！为了避免这种情况，你可以使用 Yoda notation 所以而不是比较
You should compare (==) instead of assigning (=). It can be very dangerous! To avoid such situations you can use Yoda notation so instead of comparing
address1.compareTo(address2) == 1
你可以比较一下:
1 == address1.compareTo(address2)
如果缺少=，则会出现比较错误.
In case of missing =, there will be comparation error.
在你的情况下，比较一下会更好:
In your case, it would be better to compare:
address1.compareTo(address2) > 0
