问题描述
我正在使用模拟器玩掷骰子,我试图从同一个方法返回两个值(或者更确切地说,我愿意).
I am using a simulator to play craps and I am trying to return two values from the same method (or rather I would like to).
当我写我的退货声明时,我只是试着把&"编译并正常运行;但我无法访问第二个返回值.
When I wrote my return statement I simply tried putting "&" which compiled and runs properly; but I have no way of accessing the second returned value.
public static int crapsGame(){ int myPoint; int gameStatus = rollagain; int d1,d2; int rolls=1; d1 = rollDice(); d2 = rollDice(); switch ( d1+d2 ) { case 7: case 11: gameStatus = win; break; case 2: case 3: case 12: gameStatus = loss; break; default: myPoint = d1+d2; do { d1=rollDice(); d2=rollDice(); rolls++; if ( d1+d2 == myPoint ) gameStatus = win; else if ( d1+d2 == 7 ) gameStatus = loss; } while (gameStatus == rollagain); } // end of switch return gameStatus & rolls; }
当我将值返回为:
gameStatus=crapsGame();
它适当地将变量设置为赢或输,但如果我尝试像以下语句一样简单的事情:
It appropriately sets the varaible to win or lose but if I try something as simple as following that statement with:
rolls=crapsGame();
它被赋予与游戏状态相同的值...一个 0 或一个 1(赢或输).有什么方法可以访问第二个返回值?还是有完全不同的方法?
It is assigned the same value as gamestatus...a 0 or a 1 (win or lose). Any way that I can access the second returned value? Or is there a completely different way to go about it?
推荐答案
创建自己的值持有者对象来保存这两个值,然后返回它.
Create your own value holder object to hold both values, then return it.
return new ValueHolder(gameStatus, rolls);
可以返回一个包含多个值的数组,但这很神秘,而且对可读性没有任何帮助.更容易理解这意味着什么......
It's possible to return an array with multiple values, but that's cryptic and it does nothing for readability. It's much easier to understand what this means...
valueHolder.getGameStatus()
比这意味着什么.
intArray[0]