问题描述
public int computeStyle(String season) { if(season.equals("summer")){ if (this.style.equals("toque")){ return 8; } if (this.style.equals("sun visor")){ return 1; } if (this.style.equals("fedora")){ return 6; } } else if(season.equals("winter")){ if (this.style.equals("toque")){ return 1; } if (this.style.equals("sun visor")){ return 8; } if (this.style.equals("fedora")){ return 7; } } else return 5; }
为什么我总是收到方法必须返回 int 类型的错误.这个功能有什么问题?它应该在所有可能的情况下都返回一个 int 对吧?
Why do I keep getting the error that the method must return type int. What is wrong with this function? It should return an int in every possible scenario right?
推荐答案
有两个路径没有涉及:
public int computeStyle(String season) { if(season.equals("summer")){ if (this.style.equals("toque")){ return 8; } if (this.style.equals("sun visor")){ return 1; } if (this.style.equals("fedora")){ return 6; } //here } else if(season.equals("winter")){ if (this.style.equals("toque")){ return 1; } if (this.style.equals("sun visor")){ return 8; } if (this.style.equals("fedora")){ return 7; } //here } else return 5; }
解决方法:用默认返回值声明一个变量并正确赋值:
Solution: declare a variable with the defaut return value and assign the value properly:
public int computeStyle(String season) { int result = 5; if(season.equals("summer")){ if (this.style.equals("toque")){ result = 8; } if (this.style.equals("sun visor")){ result = 1; } if (this.style.equals("fedora")){ result = 6; } } else if(season.equals("winter")){ if (this.style.equals("toque")){ result = 1; } if (this.style.equals("sun visor")){ result = 8; } if (this.style.equals("fedora")){ result = 7; } } return result; }