问题描述
我正在编写一个连接4游戏,在其中您可以选择棋盘的大小。这个游戏对于大多数棋盘大小都能完美地运行,但当棋盘比棋盘宽时,我会遇到问题。我不断得到索引超出范围的错误,我不确定我做错了什么。这就是我目前的支票功能,因为它是唯一有问题的部分。
def checkOWin(board): boardHeight = len(board) boardWidth = len(board[0]) tile = 'O' # check horizontal spaces for y in range(boardHeight): for x in range(boardWidth - 3): if board[x][y] == tile and board[x+1][y] == tile and board[x+2][y] == tile and board[x+3][y] == tile: return True # check vertical spaces for x in range(boardWidth): for y in range(boardHeight - 3): if board[x][y] == tile and board[x][y+1] == tile and board[x][y+2] == tile and board[x][y+3] == tile: return True # check / diagonal spaces for x in range(boardWidth - 3): for y in range(3, boardHeight): if board[x][y] == tile and board[x+1][y-1] == tile and board[x+2][y-2] == tile and board[x+3][y-3] == tile: return True # check diagonal spaces for x in range(boardWidth - 3): for y in range(boardHeight - 3): if board[x][y] == tile and board[x+1][y+1] == tile and board[x+2][y+2] == tile and board[x+3][y+3] == tile: return True return False
如有任何帮助或建议,将不胜感激。提前感谢!
推荐答案
您刚刚混淆了维度,您应该这样设置它们:
def checkOWin(board): boardHeight = len(board[0]) boardWidth = len(board)
因为当您引用board[x]时,这是计算董事会中列表的数量,而当您引用board[x][y]时,只是指董事会中某一特定行的长度。
if board[x][y] == tile and board[x+1][y] == tile and board[x+2][y] == tile and board[x+3][y] == tile:
当我翻转这些值时,函数运行没有错误。