问题描述
我有一个值为 7 (0b00000111) 的整数,我想用 13 (>0b00001101).替换整数中的位的最佳算法是什么?
I have an integer with a value 7 (0b00000111) And I would like to replace it with a function to 13 (0b00001101). What is the best algorithm to replace bits in an integer?
例如:
set_bits(somevalue, 3, 1) # What makes the 3rd bit to 1 in somevalue?
推荐答案
这些适用于任何大小的整数,甚至大于 32 位:
These work for integers of any size, even greater than 32 bit:
def set_bit(value, bit): return value | (1<<bit) def clear_bit(value, bit): return value & ~(1<<bit)
如果你喜欢简短的东西,你可以使用:
If you like things short, you can just use:
>>> val = 0b111 >>> val |= (1<<3) >>> '{:b}'.format(val) '1111' >>> val &=~ (1<<1) '1101'