问题描述
如何在 Python 中将二进制字符串转换为对应的十六进制值?
我有 0000 0100 1000 1101 我想获得 048D 我正在使用 Python 2.6.
int 给定 base 2 然后 hex:
>>>整数('010110',2)22>>>十六进制(整数('010110',2))'0x16'>>>>>>十六进制(整数('0000010010001101',2))'0x48d'
int的文档:
<块引用>int(x[, base]) ->整数如果可能,将字符串或数字转换为整数.一个漂浮的
点参数将被截断为零(这不包括字符串浮点数的表示!)转换字符串时,利用可选基地.转换 a 时提供碱基是错误的非字符串.如果基数为零,则根据字符串内容.如果参数超出整数范围将改为返回长对象.
hex的文档:
<块引用>十六进制(数字)->细绳返回整数或长整数的十六进制表示
整数.
How can I perform a conversion of a binary string to the corresponding hex value in Python?
I have 0000 0100 1000 1101 and I want to get 048D I'm using Python 2.6.
int given base 2 and then hex:
>>> int('010110', 2) 22 >>> hex(int('010110', 2)) '0x16' >>> >>> hex(int('0000010010001101', 2)) '0x48d'
The doc of int:
int(x[, base]) -> integer Convert a string or number to an integer, if possible. A floatingpoint argument will be truncated towards zero (this does not include a string representation of a floating point number!) When converting a string, use the optional base. It is an error to supply a base when converting a non-string. If base is zero, the proper base is guessed based on the string content. If the argument is outside the integer range a long object will be returned instead.
The doc of hex:
hex(number) -> string Return the hexadecimal representation of an integer or longinteger.