问题描述
我有一个 Electron 项目,它使用 NodeJS 的 child_process 模块执行一些 python 脚本.我的 python 脚本位于项目的根文件夹中.
I have a Electron project which executes some python script using NodeJS's child_process module. My python script is in the root folder of my project.
以下是我如何调用 python 脚本:
Here's how I call the python script:
let py = spawn('python',['ResolvePosition.py', obsFilePath, navFilePath]) py.stdout.on('data', data => console.log('data : ', data.toString())) py.on('close', ()=>{ // Python ends, do stuff })
如果我使用 npm start 运行我的电子应用程序,这很好用当我使用 npm 模块 electron-builder 为 Windows 构建可执行文件并从 dist/win-unpacked/my-app.exe 运行可执行文件时,这将不起作用,似乎我的脚本无法使用 python ./my-script-py.
This works fine if I run my electron app with npm start When I build an executable for Windows using the npm module electron-builder and run the executable from dist/win-unpacked/my-app.exe, this won't work, it seems that my script is not accesible with python ./my-script-py.
那么,我怎样才能使这个代码适用于构建的项目?
So, how can I make this code works for the built project?
推荐答案
您可以将脚本包含在 extraResources:
You can include the script in extraResources:
"build": { "extraResources": "python_scripts", ...
然后目录将位于应用根目录:
And then the dir will be at the app root:
let python = spawn('python', [path.join(app.getAppPath(), '..', 'python_scripts/my_script.py'])