问题描述
在 Python 中,如何将 datetime.datetime 转换为从 time.time 函数获得的那种 float?
In Python, how do I convert a datetime.datetime into the kind of float that I would get from the time.time function?
推荐答案
使用时间元组方法不难,仍然保留微秒:
It's not hard to use the time tuple method and still retain the microseconds:
>>> t = datetime.datetime.now() >>> t datetime.datetime(2011, 11, 5, 11, 26, 15, 37496) >>> time.mktime(t.timetuple()) + t.microsecond / 1E6 1320517575.037496