其实我不懂內涵
问题描述
我在 python 2.5 中有一个应用程序，它通过 suds 0.3.6 发送数据.
I have an application in python 2.5 which sends data through suds 0.3.6.
问题是数据包含非ascii字符，所以我需要soap消息中存在以下标头:
The problem is that the data contains non-ascii characters, so I need the following header to exist in the soap message:
Content-Type="text/html; charset="utf-8"
而 SOAP 消息中存在的标头只是:
and the header that exists in the SOAP message is just:
Content-Type="text/html"
我知道它在 suds 0.4 中已修复，但它需要 Python2.6，我需要 Python2.5，因为我使用 CentOS，它需要那个版本.所以问题是:
I know that it is fixed in suds 0.4, but it requires Python2.6 and I NEED Python2.5 because I use CentOS and it needs that version. So the question is:
如何更改或添加新的 HTTP 标头到 SOAP 消息?
How could I change or add new HTTP headers to a SOAP message?
推荐答案
当你在 urllib2 中创建 opener 时，你可以使用一些处理程序来做任何你想做的事情.例如，如果你想在 suds 中添加一个新的 header，你应该这样做:
When you create the opener in urllib2, you can use some handlers to do whatever you want. For example, if you want to add a new header in suds, you should do something like this:
https = suds.transport.https.HttpTransport() opener = urllib2.build_opener(HTTPSudsPreprocessor) https.urlopener = opener suds.client.Client(URL, transport = https)
HTTPSudsPreprocessor 是您自己的处理程序，它应该如下所示:
where HTTPSudsPreprocessor is your own handler, and it should look like this:
class HTTPSudsPreprocessor(urllib2.BaseHandler):
def http_request(self, req):
req.add_header('Content-Type', 'text/xml; charset=utf-8')
return req
https_request = http_request
您必须覆盖的方法取决于您想要做什么.请参阅 Python.org 中的 urllib2 文档
The methods you have to override depend on what you want to do. See urllib2 documentation in Python.org
