问题描述
我有一个目录,其中包含许多按特定顺序命名的文本文件:
I have a directory containing a lot of textfiles named in a specific order:
0.txt 1.txt 2.txt .... 100.txt 101.txt ..... 40000.txt
当我试图检索我正在使用的所有文件的排序列表时:
When im trying to retrieve a sorted list of all the files im using:
for file in sorted(os.listdir(filepath)): print(file)
我得到的结果是:
0.txt 1.txt 10.txt 100.txt 1000.txt 10000.txt 10001.txt 10002.txt 10003.txt 10004.txt .....
这不是我想要的,我想要它按正常的升序排列:
Which is not how i want it, i want it in normal ascending order:
0.txt 1.txt 2.txt 3.txt 4.txt ...
有人知道怎么做吗?
推荐答案
可以使用 lambda 表达式
Could use a lambda expression
import os filelist = os.listdir(path) filelist = sorted(filelist,key=lambda x: int(os.path.splitext(x)[0])) for file in filelist: print(file)
输出为:
1.txt 2.txt 3.txt 4.txt 5.txt 6.txt 7.txt 8.txt 9.txt 10.txt