问题描述
有什么方法可以判断一个字符串是否代表一个整数(例如,'3'、'-17'而不是'3.14' 或 'asfasfas') 不使用 try/except 机制?
Is there any way to tell whether a string represents an integer (e.g., '3', '-17' but not '3.14' or 'asfasfas') Without using a try/except mechanism?
is_int('3.14') == False is_int('-7') == True
推荐答案
如果你真的对到处使用 try/except 感到厌烦,请写一个辅助函数:
If you're really just annoyed at using try/excepts all over the place, please just write a helper function:
def RepresentsInt(s): try: int(s) return True except ValueError: return False >>> print RepresentsInt("+123") True >>> print RepresentsInt("10.0") False
要准确覆盖 Python 认为是整数的所有字符串,将需要更多代码.我说这只是pythonic.
It's going to be WAY more code to exactly cover all the strings that Python considers integers. I say just be pythonic on this one.