问题描述
我正在尝试从 twitter 中获取与用户名相关的用户位置.
I am trying to scrape user location with respect to user names from twitter.
输入:用户列表有超过50K个用户名
Input: The user list has more than 50K User names
AkkiPritam,6.77E+17,12/15/2015,#chennaifloods AkkiPritam,6.77E+17,12/15/2015,#bhoomikatrust AkkiPritam,6.77E+17,12/15/2015,#akshaykumar gischethans,6.77E+17,12/15/2015,#chennaifloods mid_day,6.77E+17,12/15/2015,#bollywood mid_day,6.77E+17,12/15/2015,#chennaifloods Nanthivarman16,6.77E+17,12/15/2015,#admkfails Nanthivarman16,6.77E+17,12/15/2015,#jayafails Nanthivarman16,6.77E+17,12/15/2015,#stickergovt Nanthivarman16,6.77E+17,12/15/2015,#chennaifloods AdilaMatra,6.77E+17,12/15/2015,#chennaifloods AdilaMatra,6.77E+17,12/15/2015,#climatechange AdilaMatra,6.77E+17,12/15/2015,#delhichokes AdilaMatra,6.77E+17,12/15/2015,#smog HDFCERGOGIC,6.77E+17,12/15/2015,#chennaifloods HDFCERGOGIC,6.77E+17,12/15/2015,#tnfloods ImSoorej,6.77E+17,12/15/2015,#chennaifloods ImSoorej,6.77E+17,12/15/2015,#chennaimicr
代码:我想查找地理位置,可能是地理坐标.
Code: I want to find geo location possibly geo coordinates.
from __future__ import print_function import tweepy from tweepy import OAuthHandler from tweepy import Stream from tweepy.streaming import StreamListener import pandas as pd import csv consumer_key = 'xyz' consumer_secret = 'xyz' access_token = 'xyz' access_token_secret = 'xyz' data = pd.read_csv('user_keyword.csv') df = ['user_name', 'user_id', 'date', 'keyword'] def get_user_details(username): userobj = api.get_user(username) return userobj if __name__ == '__main__': #authenticating the app (https://apps.twitter.com/) auth = tweepy.auth.OAuthHandler(consumer_key, consumer_secret) auth.set_access_token(access_token, access_token_secret) api = tweepy.API(auth) username = df['user_name'] userOBJ = get_user_details(username) print(userOBJ.location)
错误:无法将用户名解析为程序.
Error: Trouble parsing the usernames into program.
Traceback (most recent call last): File "user_profile_location.py", line 38, in <module> username = df['user_name'] TypeError: list indices must be integers, not str
推荐答案
你正在使用'data'来定义你的DataFrame和'df'我认为应该是DataFrame的列
You are using 'data' to define your DataFrame and 'df' for what I think should be the columns of the DataFrame
data = pd.read_csv('user_keyword.csv') df = ['user_name', 'user_id', 'date', 'keyword']
我假设 user_keyword.csv 文件没有标题,尝试添加:
I assume that the user_keyword.csv file has no header, try adding:
data.columns = df
它会将列名更改为存储在 df 中的值.然后稍后代替:
It will change the column names to the values stored in df. Then later instead of:
username = df['user_name']
试试:
username = data['user_name']
请记住,现在用户名是一整列,因此 get_user_details(username) 不应期待单个字符串.
Keep in mind that now username is a whole column so get_user_details(username) should not be expecting a single string.