问题描述
我有一个 char[] 类型的变量,我想在其中复制 NSString 值.如何将 NSString 转换为 char 数组?
I have a variable of type char[] and I want to copy NSString value in it. How can I convert an NSString to a char array?
推荐答案
使用-[NSString UTF8String]:
NSString *s = @"Some string"; const char *c = [s UTF8String];
您也可以使用 -[NSString cStringUsingEncoding:] 如果你的字符串是用非 UTF-8 编码的.
You could also use -[NSString cStringUsingEncoding:] if your string is encoded with something other than UTF-8.
一旦你有了 const char *,你就可以像使用 chars 数组一样使用它:
Once you have the const char *, you can work with it similarly to an array of chars:
printf("%c ", c[5]);
如果要修改字符串,请复制:
If you want to modify the string, make a copy:
char *cpy = calloc([s length]+1, 1); strncpy(cpy, c, [s length]); // Do stuff with cpy free(cpy);