问题描述
我尝试解析以下类型的 XML(数据来自 getMembers.php):
I try parsing the following type of XML (data from getMembers.php):
<?xml version="1.0" encoding="ISO-8859-1"?> <members> <id>3422345</id> <name>Bill Gates</name> <id>232311</id> <name>Bob Barker</name> </members>
我使用下面的代码来解析它:
And I use the code below to parse it:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function () { $.ajax({ type: "GET", url: "getMembers.php", cache: false, dataType: "xml", success: function(xml) { $(xml).find('members').each(function(){ var name = $(this).find("name").text() alert(name); }); } }); }); </script>
没有错误,但我同时得到了两个名字.
No error but I get both names at the same time.
喜欢:
比尔·盖茨鲍勃·巴克<--第一次循环>
Bill GatesBob Barker <--first loop>
代替
比尔盖茨<--第一个循环>
Bill Gates <--first loop>
Bob Barker <--第二个循环>
Bob Barker <--second loop>
任何帮助都会很棒!
推荐答案
我认为你迭代的是成员,而不是名字:
I think you iterate over members, not names:
success: function(xml) { $(xml).find('members').each(function(){ $(this).find("name").each(function(){ var name = $(this).text(); alert(name); }); }); }
或者您的 XML 应该如下所示:
Or maybe your XML should looks like:
<members> <id>3422345</id> <name>Bill Gates</name> </members> <members> <id>232311</id> <name>Bob Barker</name> </members>