问题描述
我正在尝试将 6 位日期转换为常规日期.
I'm trying to convert a 6 digit date into a regular looking date.
目前我们在数据库中有这个:
Currently we have this in the DB:
734562 734776 734837
这是我正在尝试的:
select timestampadd( sql_tsi_day ,rbaging.billing_period_end ,cast('0001-01-01' as sql_timestamp) ) -1,* from [kslap208].[c021]..RB_Resident_Aging rbaging
我得到的错误是:
Msg 195, Level 15, State 10, Line 5 'timestampadd' is not a recognized built-in function name.
如何将此字段转换为常规日期字段?
how do i convert this field into a regular date field?
推荐答案
如果远程源是一个整数,或者可以强制转换为一个,我相信应该这样做:
If the remote source is an integer, or can be cast to one, I believe this should do it:
SELECT DATEADD(DD, Field - 730000, '2001-01-01')