问题描述

所以我的查询:

SELECT Tags, COUNT(Tags) AS Listings
FROM Job
WHERE datepart(year, dateposted)=2013
GROUP BY Tags
ORDER BY Listings DESC

输出:

+----------------------+----------+
|         Tags         | Listings |
+----------------------+----------+
| java c++             |       41 |
| software development |       41 |
| java c++ c#          |       31 |
|                      |       25 |
| sysadmin             |       25 |
| see jd               |       24 |
| java c++ ood         |       23 |
| java                 |       23 |
+----------------------+----------+

我希望它像这样出来:

+----------------------+----------+
|         Tags         | Listings |
+----------------------+----------+
| java                 |       118|
| c++                  |       95 |
| ood                  |       23 |
| see                  |       24 |
| jd                   |       24 |
| software development |       41 |
| sysadmin             |       25 |
| c#                   |       31 |
+----------------------+----------+

如何计算字段中的每个单词而不是整个字段?标签列是 nvarchar.

How can I count each individual word in the field instead of the entire field? The tags column is nvarchar.

推荐答案

我就是这样解决问题的.

This is how I solved my issue.

SELECT TOP 50 Tags.s Tag, COUNT(Tags.s) AS Listings
FROM Job
CROSS APPLY [dbo].[SplitString](Tags,' ') Tags
WHERE NOT Job.Tags IS NULL and datepart(year,job.datecreated) = 2013
GROUP BY Tags.s
ORDER BY Listings DESC