奥巴驴g
问题描述
我试过如下.
MyList.RemoveAll(t => t.Name == "ABS"); MyList.RemoveAll(t => t.Name == "XYZ"); MyList.RemoveAll(t => t.Name == "APO");
相反，我该怎么做:
MyList.RemoveAll(t => t.Name == "ABS" || t => t.Name == "XYZ" ||t => t.Name == "APO");
推荐答案
你只需要 一个 lambda 表达式 - || 就在其中:
You only need one lambda expression - the || goes within that:
MyList.RemoveAll(t => t.Name == "ABS" || t.Name == "XYZ" || t.Name == "APO");
换句话说，给定一个 t，如果 t.Name 是 ABS，或者如果 t.Name> 是 XYZ，或者如果 t.Name 是 APO."
In other words, "Given a t, I want to remove the element if t.Name is ABS, or if t.Name is XYZ, or if t.Name is APO."
那里只有一个给定一个 t"，这就是 t => 部分的有效含义.
There's only one "given a t" in there, which is what the t => part means, effectively.
