Ajax 上传图片并预览的简单实现

1. 直接上最简单的一种 ajax 异步上传图片，并预览

html：

<!doctype html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8">
<title>图片上传 | cookie</title>
</head>
<body>
  file: <input type="file" id="images" name="image" /><br><br>
  desc: <input type="text" id="desc" name="desc" /><br><br>
  <input type="button" value="upload" onclick="upload();">
  
  <div class="images"></div>
  
<script type="text/javascript" src="js/jquery-1.12.4.min.js"></script>
<script type="text/javascript" src="js/upload.js"></script>
<script type="text/javascript">
  function upload() {
    $.ajaxfileupload({
      url : 'upload.htm',
      fileelementid : 'images',
      datatype : 'json',
      data : {desc : $("#desc").val()},
      success : function(data) {
        var html = $(".images").html();
        html += '<img width="100" height="100" src="/hotelmanager/upload/' + data.url + '">'
        $(".images").html(html);
      }
    })
    return false;
  }
</script>
</body>
</html>

servlet：

protected void dopost(httpservletrequest request, httpservletresponse response)
      throws servletexception, ioexception {
    diskfileitemfactory factory = new diskfileitemfactory();
    
    servletfileupload upload = new servletfileupload(factory);
    
    string path = request.getservletcontext().getrealpath("/upload");
    string name = null;
    try {
      list<fileitem> items = upload.parserequest(request);
      for (fileitem item : items) {
        if(item.isformfield()){
          system.out.println(item.getfieldname() + ": " + item.getstring());
        } else {
          name = item.getname();
          item.write(new file(path,name));
        }
      }
      printwriter out = response.getwriter();
      out.print("{");
      out.print("url:"" + name +""");
      out.print("}");
      
    } catch (exception e) {
      e.printstacktrace();
    }
  }

2. 这里会用到一个 ajaxupload.js，网上多得很。

以上就是小编为大家带来的ajax 上传图片并预览的简单实现的全部内容了，希望对大家有所帮助，多多支持~