问题描述

I am a relative newby to Python and SO. I have an xml file from which I need to extract information. I've been struggling with this for several days, but I think I finally found something that will extract the information properly. Now I'm having troubles getting the right output. Here is my code:

from xml import etree
node = etree.fromstring('<dataObject><identifier>5e1882d882ec530069d6d29e28944396</identifier><description>This is a paragraph about a shark.</description></dataObject>')
identifier = node.findtext('identifier')
description = node.findtext('description')
print identifier, description

The result that I get is "5e1882d882ec530069d6d29e28944396 This is a paragraph about a shark.", which is what I want.

However, what I really need is to be able to read from a file instead of a string. So I try this code:

from xml import etree
node = etree.parse('test3.xml')
identifier = node.findtext('identifier')
description = node.findtext('description')
print identifier, description

Now my result is "None None". I have a feeling I'm either not getting the file in right or something is wrong with the output. Here is the contents of test3.xml

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<response xmlns="http://www.eol.org/transfer/content/0.3" xmlns:dc="http://www.51sjk.com/Upload/Articles/1/0/335/335575_20221101155250405.jpg" xmlns:dwc="http://www.51sjk.com/Upload/Articles/1/0/335/335575_20221101155254030.jpg" xmlns:dcterms="http://www.51sjk.com/Upload/Articles/1/0/335/335575_20221101155255607.jpg" xmlns:xsi="http://www.51sjk.com/Upload/Articles/1/0/335/335575_20221101155257608.jpg" xmlns:geo="http://www.51sjk.com/Upload/Articles/1/0/335/335575_20221101155258185.jpg" xmlns:dwct="http://www.51sjk.com/Upload/Articles/1/0/335/335575_20221101155258467.jpg" xsi:schemaLocation="http://www.eol.org/transfer/content/0.3 http://services.eol.org/schema/content_0_3.xsd">
  <identifier>5e1882d822ec530069d6d29e28944369</identifier>
  <description>This is a paragraph about a shark.</description>

Your XML file uses a default namespace. You need to qualify your searches with the correct namespace:

identifier = node.findtext('{http://www.eol.org/transfer/content/0.3}identifier')

for ElementTree to match the correct elements.

You could also give the .find(), findall() and iterfind() methods an explicit namespace dictionary. This is not documented very well:

namespaces = {'eol': 'http://www.eol.org/transfer/content/0.3'} # add more as needed

root.findall('eol:identifier', namespaces=namespaces)

Prefixes are only looked up in the namespaces parameter you pass in. This means you can use any namespace prefix you like; the API splits off the eol: part, looks up the corresponding namespace URL in the namespaces dictionary, then changes the search to look for the XPath expression {http://www.eol.org/transfer/content/0.3}identifier instead.

If you can switch to the lxml library things are better; that library supports the same ElementTree API, but collects namespaces for you in a .nsmap attribute on elements.