问题描述

我有 2 种口味，比如说香草和巧克力.我也有 Debug 和 Release 构建类型，我需要 Vanilla Release 的字段为 true，而其他 3 个组合应该为 false.

I have 2 flavors, lets say Vanilla and Chocolate. I also have Debug and Release build types, and I need Vanilla Release to have a field true, while the other 3 combinations should be false.

def BOOLEAN = "boolean"
def VARIABLE = "VARIABLE"
def TRUE = "true"
def FALSE = "false"

    VANILLA {

        debug {

            buildConfigField BOOLEAN, VARIABLE, FALSE

        }

        release {

            buildConfigField BOOLEAN, VARIABLE, TRUE

        }


    }

    CHOCOLATE {
        buildConfigField BOOLEAN, VARIABLE, FALSE
    }

我遇到了一个错误，所以我猜调试和发布技巧不起作用.可以这样做吗?

I'm having an error, so I guess the debug and release trick doesnt work. It is possible to do this?

推荐答案

循环变体并检查它们的名称:

Loop the variants and check their names:

productFlavors {
    vanilla {}
    chocolate {}
}

applicationVariants.all { variant ->
    println("Iterating variant: " + variant.getName())
    if (variant.getName() == "chocolateDebug") {
        variant.buildConfigField "boolean", "VARIABLE", "true"
    } else {
        variant.buildConfigField "boolean", "VARIABLE", "false"
    }
}