问题描述
我有以下数据库表:
Date Return Index 01-01-2020 0.1 Null 01-02-2020 0.2 Null 01-03-2020 0.3 Null
我想使用以下公式更新索引值:
I would like to update the Index value using the following formula:
Index = (Previous_Month_Index * Return) + Previous_Month_Index (Use 100 for Previous_Month_Index for the first month)
预期结果:(按日期升序计算的索引)
Expected Result: (Index to be calculated order by Date asc)
Date Return Index 01-01-2020 0.1 110 -- (100 + 10) 01-02-2020 0.2 132 -- (110 + (110 * 0.20)) = 110 + 22 = 132 01-03-2020 0.3 171.6 -- (132 + (132 * 0.30)) = 132 + 39.6 = 171.6
如何使用 SQL 执行此操作?我尝试了以下查询,但出现错误:
How can I do this using SQL? I tried the following query but getting an error:
窗口函数不能在另一个窗口函数或聚合的上下文中使用.
Windowed functions cannot be used in the context of another windowed function or aggregate.
--first, load the sample data to a temp table select * into #t from ( values ('2020-01-01', 0.10), ('2020-02-01', 0.20), ('2020-03-01', 0.30) ) d ([Date], [Return]); --next, calculate cumulative product select *, CumFactor = cast(exp(sum(log(case when ROW_NUMBER() OVER(order by [Date] ASC) = 1 then 100 * [Return] else [Return] end)) over (order by [Date])) as float) from #t; drop table #t
推荐答案
从数学上来说,你想要的结果相当于这个产品:
Thinking mathematically, the result that you want is equivalent to this product:
100 * (1 + a1) * (1 + a2) * (1 + a3) * ....
其中 a1、a2、a3 是 [Return] 列的值.
where a1, a2, a3 are the values of the column [Return].
该产品可以通过以下方式获得:
This product can be obtained by:
100 * EXP(SUM(LOG(1 + [Return])))
你可以在 sql 中这样做:
and you can do this in sql like this:
SELECT *, 100 * EXP(SUM(LOG(1 + [Return])) OVER (ORDER BY [Date])) [Index] FROM #t
请参阅演示.